Case Scenario
Suppose that there are 10 subjects with eyelid measurements from three different observes (making the total sample = 30), who used a new computerized technique to get eyelid images and later measured the parameters using image J software. What would you do to test for reliability of measurements and how would you go by performing this analysis? Please note that the dependent variable (eyelid measurement) is a continuous variable. This is a real example.
Approach
The best measure of reliability for continuous data is the Intraclass Correlation Coefficient (ICC). The ICC would inform you about the inter-rater reliability, where the higher the ICC the less unique information each additional measure provides.
Where S2w is the pooled variance within subjects, and S2b is the variance of the measurements between subjects. S2b + S2w is the total variance. As such, the ICC is interpreted as the proportion of total variance accounted for by the within-subject variation.
You can get the limits on the icc scale using 0.9740 +/- 1.96*0.01399 (which presumably is what is shown in the output as lower and upper limits; values may slightly differ when calculating by hand versus the automated).
Again, the Fisher's Z limits are (1.5483, 2.7819) which also presumably is from:
You would then use the conversion formula to get the 95% CI on the ICC scale
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Where S2w is the pooled variance within subjects, and S2b is the variance of the measurements between subjects. S2b + S2w is the total variance. As such, the ICC is interpreted as the proportion of total variance accounted for by the within-subject variation.
You would
usually want to calculate a 95% confidence interval along with the ICC. However,
because the ICC is a bounded parameter (is only between 0 and 1), it is better
to transform the ICC to an unbounded scale and do the confidence interval
calculation on that scale (and then go back to the original scale once you get
the limits). You would need to calculate the 95% CI of the Fisher's Z
transformation of the ICC and then convert these limits to the ICC
scale.
The SAS code
below is an example of how you can do this using NLMIXED for a random intercept
model:
/* random intercept model for Palpebral */
proc nlmixed data=eyelid.interod
gconv=1e-12;
parms b0=3 varu=1 vare=1;
mean = b0 +u;
model Palpebral ~ normal(mean,vare);
random u ~ normal(0,varu) subject=id;
estimate 'icc' varu / (varu + vare);
estimate 'Fisher z of icc' 0.5 * log((1 +
(varu / (varu + vare))) / (1 - (varu / (varu + vare))));
run;
This code
will give you an output that includes the below:
Additional Estimates
Standard
Label
Estimate
Error DF t Value Pr >
|t| Alpha
Lower Upper
icc
0.9740
0.01399 9
69.64 <.0001
0.05 0.9424
1.0057
Fisher z of icc
2.1651
0.2727
9 7.94
<.0001 0.05
1.5483 2.7819
You can get the limits on the icc scale using 0.9740 +/- 1.96*0.01399 (which presumably is what is shown in the output as lower and upper limits; values may slightly differ when calculating by hand versus the automated).
Again, the Fisher's Z limits are (1.5483, 2.7819) which also presumably is from:
2.1651 +/-
1.96*0.2727
You would then use the conversion formula to get the 95% CI on the ICC scale
r = (exp(2z)
- 1) / (exp(2z) + 1)
In this
example you will get the 95% CI as (0.914-0.992). This seems like to be a much
better fit. There are times when it may not matter whether you get the 95% CI
with the raw scale or the Fisher-transformed scale. However, in certain cases
like this (with a high ICC), you definitely need the Fischer z-transformation.
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References and Additional Readings:
Euser AM, Cessie S, Finken MJJ, Wit JM, Dekker FW. Reliability studies can be designed more efficiently by using variance components estimates from different sources. J Clin Epidemiol 2007; 60: 1010-1014.
Longitudinal course at the SPH, UIC given by Dr. Don Hedeker http://tigger.uic.edu/~hedeker/ml.html
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